If the breadth and perimeter of a rectangle are in the ratio 1 : 8 and the area of rectangle is 363 cm², then the breadth of the rectangle is :

11 cm

Here,

B : 2(L + B)

1  :   8

and L × B = 363 cm²

⇒ 8 = 2(L + 1)

⇒ 4 = L + 1

⇒ L = 3,

Now,

⇒ (3 x 1)\( {x }^{2 } \) = 363

⇒ 3( {x }^{2 } \) = 363

⇒ ( {x }^{2 } \) = 121

⇒ x = 11.

⇒ Breadth = 1 x 11 = 11 cm