In a ΔABC, right-angled at B, AB = 5 cm and (AC - BC) = 1 cm. The value \(\sec {C} + \cot {A}\) of is?
Answer & explanation
Correct answer: option 1
AC - BC = 1
triplets = 5, 12, 13
Sec C + Cot A = \(\frac{13}{12}\) + \(\frac{5}{12}\) = \(\frac{18}{12}\) = \(\frac{3}{2}\)