A and B are events such that P(A)= 0.4,

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Probability

Question:

A and B are events such that P(A)= 0.4, P(B)=0.3 and P(A ∪ B)= 0.5, then P(B ∩ A') is equal to :

Options:

0.2

0.1

0.3

0.4

Correct Answer:

0.1

Explanation:

The correct answer is option (2) → 0.1 $\frac{80}{89}$

$P(B ∩ A')=P(B)-P(A ∩ B)$ ...(1)

we know that

$P(A∪B)+P(A ∩ B)=P(A)+P(B)$

$P(A ∩ B)=P(A)+P(B)-P(A∪B)$

$=0.4+0.3-0.0.2=P(A ∩ B)$

so from (1) $P(B ∩ A')=0.3-0.2=0.1$