The set of values of 'x' for which $37-(3x+5)≥9x-8(x-3)$ holds true is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (-∞, 2]
$37-(3x+5)≥9x-8(x-3)$
$⇒32-3x≥x+24$
$⇒8≥4x$
$⇒x≤2$
$⇒x∈(-∞, 2]$
The set of values of 'x' for which $37-(3x+5)≥9x-8(x-3)$ holds true is :
Correct answer: option 1
The correct answer is Option (1) → (-∞, 2]
$37-(3x+5)≥9x-8(x-3)$
$⇒32-3x≥x+24$
$⇒8≥4x$
$⇒x≤2$
$⇒x∈(-∞, 2]$