CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
The set of values of 'x' for which $37-(3x+5)≥9x-8(x-3)$ holds true is :
(-∞, 2]
[2, ∞)
(-∞, 2)
(2, ∞)
The correct answer is Option (1) → (-∞, 2]
$37-(3x+5)≥9x-8(x-3)$
$⇒32-3x≥x+24$
$⇒8≥4x$
$⇒x≤2$
$⇒x∈(-∞, 2]$
