Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

The lines$\frac{x}{1}=\frac{y}{2}=\frac{z}{3}$ and $\frac{x-1}{-2}=\frac{y-2}{-4}=\frac{z-3}{-6}$ are

Options:

coincident

skew

intersecting

parallel

Correct Answer:

parallel

Explanation:

Clearly, direction ratios of two lines are proportional i.e. $\frac{1}{-2}=\frac{2}{-4}=\frac{3}{-6}$

So, given lines are parallel.