L is the incentre of ΔONP. If ∠OLP + ∠ONP = 195 degree, then what will be the value of ∠OLP?

125 degree

\(\angle\)OLP + \(\angle\)ONP = 195

\(\angle\)OLP = 195 - \(\angle\)ONP

L is the incenter.

\(\angle\)OLP = 90 + \(\angle\)ONP/2

195 - \(\angle\)ONP = 90 + \(\angle\)ONP/2

105 = 3\(\angle\)ONP/2

\(\angle\)ONP = 70

\(\angle\)OLP = 195 - 70

\(\angle\)OLP = 125

Therefore, \(\angle\)OLP is \({125}^\circ\).