In a certain code language, ‘WAND’ is coded as ‘232144’ and ‘EAST’ is coded as ‘621920’. Then,
A. ‘DEAF’ is coded as ‘4616’
B. ‘WEST’ is coded as ‘2361920’
C. ‘CURD’ is coded as ‘322184’
D. ‘CALM’ is coded as ‘321213’
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → B, C and D only
Each letter is replaced by a number from its place in the alphabet. The two given words show that a consonant keeps its place number, but a vowel gets one more than its place number:
WAND: W = 23, A = 1 + 1 = 2, N = 14, D = 4, giving 232144
EAST: E = 5 + 1 = 6, A = 2, S = 19, T = 20, giving 621920
A. ‘DEAF’ is coded as ‘4616’ Incorrect. D = 4, E = 6, A = 2, F = 6, so DEAF is 4626. The code 4616 gives A its plain place number 1, which breaks the rule seen in WAND and EAST.
B. ‘WEST’ is coded as ‘2361920’ Correct. W = 23, E = 6, S = 19, T = 20, giving 2361920.
C. ‘CURD’ is coded as ‘322184’ Correct. C = 3, U = 21 + 1 = 22 (a vowel), R = 18, D = 4, giving 322184.
D. ‘CALM’ is coded as ‘321213’ Correct. C = 3, A = 2, L = 12, M = 13, giving 321213.