Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

$x=a(1-\sin t), y=a(1-\tan t)$, then $\frac{d y}{d x}$ is

Options:

$\sec ^2 t$

$\sec ^3 t$

$\cos ^2 t$

$\cos ^3 t$

Correct Answer:

$\sec ^3 t$

Explanation:

$x=a(1-\sin t) \Rightarrow \frac{d x}{d t}=a(0-\cos t)=-a \cos t$

$\frac{d y}{d t}=\frac{-a \sec ^2 t}{-a \cos t}=\sec ^3 t$

Hence (2) is correct answer.