$x=a(1-\sin t), y=a(1-\tan t)$, then $\frac{d y}{d x}$ is
Answer & explanation
Correct answer: option 2
$x=a(1-\sin t) \Rightarrow \frac{d x}{d t}=a(0-\cos t)=-a \cos t$
$\frac{d y}{d t}=\frac{-a \sec ^2 t}{-a \cos t}=\sec ^3 t$
Hence (2) is correct answer.