CUET Preparation Today
CUET
-- Mathematics - Section B1
Definite Integration
The value of $\int\limits_{-1}^{1} x |x| \, dx$ is:
$\frac{1}{6}$
$\frac{1}{3}$
$-\frac{1}{6}$
$0$
The correct answer is Option (4) → 0
We have,
$I = \int\limits_{-1}^{1} x |x| \, dx = 0$ [as $x |x|$ is an odd function.]
