In the reaction ${ }_1^2 H+{ }_1^3 H \rightarrow{ }_2^4 H e+{ }_0^1 n$. If the tending energies of ${ }_1^2 \mathrm{H},{ }_1^3 \mathrm{H}$ and ${ }_2^4 \mathrm{He}$ are respectively $a, b$ and $c$ (in MeV), then the energy (in MeV) released in this reaction is

c − a − b

During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c – (a + b) = c – a – b