Two dice are thrown simultaneously. What is the probability that 4 will come up on at least one die?

$\frac{11}{36}$

The correct answer is Option (1) → $\frac{11}{36}$

When two dice are thrown:

• Probability that 4 does NOT appear on one die = $\frac{5}{6}$​
• Probability that 4 does NOT appear on either die = $\left(\frac{5}{6}\right)^2 = \frac{25}{36}$​

So,
Probability that 4 appears on at least one die

$= 1 - \frac{25}{36} = \frac{11}{36}$