CUET Preparation Today
In a Binomial probability distribution if mean $=\frac{20}{3}$ and variance $=\frac{40}{9};$ then p = |
$\frac{1}{3}$ $\frac{3}{4}$ $\frac{1}{2}$ $\frac{2}{3}$ |
$\frac{1}{3}$ |
The correct answer is Option (1) → $\frac{1}{3}$ Mean, $n×p=\frac{20}{3}$ Variance, $n×p×(1-p)=\frac{40}{9}$ $⇒\frac{20}{3}(1-p)=\frac{40}{9}$ $⇒1-p=\frac{2}{3}$ $⇒p=\frac{1}{3}$ |
