$\frac{1+\sin \theta}{\cos \theta}$ is equal to which of the following (where $\theta \neq \frac{\pi}{2}$) ?
Answer & explanation
Correct answer: option 4
Given :-
\(\frac{1 + sin θ}{cos θ}\)
Multiply and divide by ( 1 - sin θ )
= \(\frac{1 + sin θ}{cos θ}\) × \(\frac{1 - sin θ}{1 - sin θ}\)
= \(\frac{(12 - sin2 θ}{cos θ ( 1 - sin θ)}\)
= \(\frac{(cos2 θ}{cos θ ( 1 - sin θ)}\)
= \(\frac{(cos θ}{( 1 - sin θ)}\)
So , Option 4 is correct .