Integral curve satisfying $y'=\frac

CUET Preparation Today

Start Free Mocks

Home Questions QXTEUBKHJX

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Integral curve satisfying $y'=\frac{x^2+y^2}{x^2-y^2}, y(1)=1$ has the slope at the point (1, 0) of the curve, equal to :

Options:

$-\frac{5}{3}$

-1

$\frac{5}{3}$

Correct Answer:

Explanation:

$\frac{d y}{d x}=\frac{x^2+y^2}{x^2-y^2}$

⇒ slope at (1,0) = $\left[\frac{d y}{d x}\right]_{(1,0)}=\frac{1+0}{1-0}=1$

Hence (3) is the correct answer.