Area lying in the first quadrant and bounded by the circle \(x^2+y^2=4\) and the lines \(x=0\) and \(x=2\) is1\(\pi\)2\(\frac{\pi}{2}\)3\(\frac{\pi}{3}\)4\(\frac{\pi}{4}\)Answer & explanation+Correct answer: option 1Required area \(=\left|\int_{0}^{2}\sqrt{4-x^2}\right|\)
