If $A=\left[\begin{array}{ll}3 & -5 \\ 4 & -7\end{array}\right]$, then $A^{-1}$ is:

$\left[\begin{array}{ll}-7 & 5 \\ -4 & 3\end{array}\right]$ $\left[\begin{array}{cc}7 & 5 \\ 4 & -3\end{array}\right]$ $\left[\begin{array}{cc}-7 & -5 \\ -4 & 3\end{array}\right]$ $\left[\begin{array}{ll}7 & -5 \\ 4 & -3\end{array}\right]$

$\left[\begin{array}{ll}7 & -5 \\ 4 & -3\end{array}\right]$

The correct answer is Option (4) → $\left[\begin{array}{ll}7 & -5 \\ 4 & -3\end{array}\right]$