The average score in Mathematics of 90 students of sections A and B together is 49. The number of students in A was 25% more than that of B, and the average score of the students in B was 20% higher than that of the students in A. What is the average score of the students in A?
Answer & explanation
Correct answer: option 2
Let number of students in section B be x
Let average score of students in A be y
Number of students in section A = 125% of B = \(\frac{5}{4}\) × x
x + \(\frac{5}{4}\)x = 90
x = 40
Number of students in section A = 50
Total score of students in section B = 40 x 120% x y
Total score of students in section B = 40 x \(\frac{6y}{5}\) = 48y
Total score of all students of A and B = 90 x 49 = 4410
50y + 48y = 98y = 4410
y = 45
Average score of students in class A is 45