Practicing Success
Practicing Success
CUET Preparation Today
The value of \(x\) for which \(\left|\begin{array}{ll}3&x\\ x&1\end{array}\right|=\left|\begin{array}{ll}3&2\\ 4&1\end{array}\right|\) is |
\(2\) \(3\) \(±2\sqrt{2}\) \(0\) |
\(±2\sqrt{2}\) |
\(\left|\begin{array}{ll}3&x\\ x&1\end{array}\right|=\left|\begin{array}{ll}3&2\\ 4&1\end{array}\right|⇒3-x^2=3-8\) $⇒x^2=8$ $⇒x=±2\sqrt{2}$ |
