CUET Preparation Today
CUET
-- Mathematics - Section B1
Continuity and Differentiability
$\underset{x→0}{\lim}|x|^{[\cos x]}$ is
1
does not exist
0
none of these
$\underset{x→0^+}{\lim}x^0=\underset{x→0^+}{\lim}1=1,\underset{x→0^-}{\lim}(-x)^0=\underset{x→0^-}{\lim}1=1$