$\underset{x→0}{\lim}|x|^{[\cos x]}$ is
Answer & explanation
Correct answer: option 3
$\underset{x→0^+}{\lim}x^0=\underset{x→0^+}{\lim}x=0,\underset{x→0^-}{\lim}(-x)^1=\underset{x→0^-}{\lim}0=0$
$\underset{x→0}{\lim}|x|^{[\cos x]}$ is
Correct answer: option 3
$\underset{x→0^+}{\lim}x^0=\underset{x→0^+}{\lim}x=0,\underset{x→0^-}{\lim}(-x)^1=\underset{x→0^-}{\lim}0=0$