Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The principal value $tan^{-1}\begin{Bmatrix}sin\left(-\frac{\pi}{2}\right)\end{Bmatrix},$ is

Options:

$\frac{\pi}{4}$

$\frac{-\pi}{4}$

$\frac{3\pi}{4}$

$-\frac{3\pi}{4}$

Correct Answer:

$\frac{-\pi}{4}$

Explanation:

We know that $sin\left(-\frac{\pi}{2}\right) = -1.$

$tan^{-1}\begin{Bmatrix}sin\left(-\frac{\pi}{2}\right)\end{Bmatrix}=tan^{-1}(-1)=-\frac{\pi}{4}$