CUET Preparation Today
The principal value $tan^{-1}\begin{Bmatrix}sin\left(-\frac{\pi}{2}\right)\end{Bmatrix},$ is |
$\frac{\pi}{4}$ $\frac{-\pi}{4}$ $\frac{3\pi}{4}$ $-\frac{3\pi}{4}$ |
$\frac{-\pi}{4}$ |
We know that $sin\left(-\frac{\pi}{2}\right) = -1.$ $tan^{-1}\begin{Bmatrix}sin\left(-\frac{\pi}{2}\right)\end{Bmatrix}=tan^{-1}(-1)=-\frac{\pi}{4}$ |
