The following system of equations has :
$x+2 y+3 z=1$
$x-y+4 z=0$
$2 x+y+7 z=1$
Answer & explanation
Correct answer: option 2
$x+2 y+3 z=1$
$x-y+4 z=0$
$2 x+y+7 z=1$
$A=\left[\begin{array}{ccc}1 & 2 & 3 \\ 1 & -1 & 4 \\ 2 & 1 & 7\end{array}\right]$ $B=\left[\begin{array}{l}1 \\ 0 \\ 1\end{array}\right]$
finding $|A|$
$|A|=\left|\begin{array}{ccc}
1 & 2 & 3 \\
1 & -1 & 4 \\
2 & 1 & 7
\end{array}\right|$
$=1\left[\begin{array}{rr}-1 & 4 \\ 1 & 7\end{array}\right]-2\left[\begin{array}{ll}1 & 4 \\ 2 & 7\end{array}\right]+3\left[\begin{array}{cc}1 & -1 \\ 2 & 1\end{array}\right]$
$=1(-7-4)-2(7-8)+3(1+2)$
$=1(-11)-2(-1)+3(3)$
$-11+2+9$
$=-11+11=0$
as |A| = 0 and every element of B is not zero
option → 2, no solution