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CUET
-- Mathematics - Section B1
Determinants
The following system of equations has : x+2y+3z=1 x−y+4z=0 2x+y+7z=1 |
a unique solution no solution infinitely many solutions only two solutions |
no solution |
x+2y+3z=1 x−y+4z=0 2x+y+7z=1 A=[1231−14217] B=[101] finding |A| |A|=|1231−14217| =1[−1417]−2[1427]+3[1−121] =1(−7−4)−2(7−8)+3(1+2) =1(−11)−2(−1)+3(3) −11+2+9 =−11+11=0 as |A| = 0 and every element of B is not zero option → 2, no solution |