CUET Preparation Today
CUET
-- Mathematics - Section B1
Definite Integration
Find $\int_{0}^1xe^xdx$
2
-1
1
0
Using integration by parts
$∫uv\,dx=u∫v\,dx-∫u'(∫v\,dx)dx$
$∫xe^x\,dx=x∫e^x\,dx-∫1.e^x\,dx$
$xe^x-e^x|_0^1$
$=(1.e^1-e^1)-(0-e^0)$
$=0-(0-1)$
$=1$
