The length of one of the diagonals of a rhombus is 48 cm. If the side of the rhombus is 26 cm, then what is the area of the rhombus?
Answer & explanation
Correct answer: option 4
We have,
The diagonals of a rhombus = 48 cm
The side of the rhombus = 26 cm
We know that,
d12 + d22 = 4a2, (where d1 and d2 are the diagonals of rhombus and a is the side)
= 482 + d22 = 4 × 262
= d22 = 2704 – 2304
= d2 = 20
Now, the area of rhombus = \(\frac{1}{2}\) × d1 × d2
= \(\frac{1}{2}\) × 48 × 20 = 480cm2