The amplitude of the magnetic field of an electromagnetic wave in vacuum is B0 = 300 nT. What is the amplitude of the electric field part of the wave? (Given speed of light in vacuum, C = 3 × 108 ms-1)
Answer & explanation
Correct answer: option 1
$E_0 = cB_0 = 3\times 10^8 \times 300\times 10^{-9} =90 N/C$