Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

The amplitude of the magnetic field of an electromagnetic wave in vacuum is B0 = 300 nT. What is the amplitude of the electric field part of the wave? (Given speed of light in vacuum, C = 3 × 108 ms-1)

Options:

90 N/C

900 N/C

9 × 103 N/C

0.9 N/C

Correct Answer:

90 N/C

Explanation:

$E_0 = cB_0 = 3\times 10^8 \times 300\times 10^{-9} =90 N/C$