If $y=\log \left(\frac{x^5}{e^5}\right)$, then $\frac{d^2 y}{dx^2}$ is,

$\frac{-5}{x^2}$ $\frac{-20}{x^4}$ $\frac{x^3}{e^2}$ $\frac{-20 x^3}{e^2}$

$\frac{-5}{x^2}$

The correct answer is Option (1) - $\frac{-5}{x^2}$