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The value of the integral $I=\int\limits^{1}_{-1}|x|dx$ is : |
0 1 $\frac{1}{2}$ 2 |
1 |
The correct answer is Option (2) → 1
$I=\int\limits^{1}_{-1}|x|dx=2\int\limits^{1}_{0}xdx$ |x| → even function $=2×\left[\frac{x^2}{2}\right]^{1}_{0}$ = 1 sq. unit |
