The value of the integral $I=\int\limits^{1}_{-1}|x|dx$ is :

0 1 $\frac{1}{2}$ 2

1

The correct answer is Option (2) → 1 $I=\int\limits^{1}_{-1}|x|dx=2\int\limits^{1}_{0}xdx$ |x| → even function $=2×\left[\frac{x^2}{2}\right]^{1}_{0}$ = 1 sq. unit