If $\alpha$ is an acute angle, $\tan \left(4 \alpha-50^{\circ}\right)=\cot \left(50^{\circ}-\alpha\right)$, then find the value of $\alpha$ (in degrees).

60° 45° 30° 90°

30°

If tanA = cot B    , Then A + B = 90º As , $\tan \left(4 \alpha-50^{\circ}\right)=\cot \left(50^{\circ}-\alpha\right)$ So , 4α - 50º  + 50º  - α  = 90º 3α = 90º α = 30º