If (a + b - c + 2x2)2 + (b + c - a + 3x2)2 + (c + a - b - 6x2)2
= 0 find the value of \(\sqrt {a+b+c}\)
Answer & explanation
Correct answer: option 4
We know that if
a2 + b2 + c2 = 0
a = 0
b = 0
c = 0
So, a + b - c = -2x2
b + c - a = -3x2
c + a - b = 6x2
By adding a + b + c = x2
\(\sqrt {a+b+c}\) = \(\sqrt {{x}^{2}}\) = ±x