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If (a + b - c + 2x2)2 + (b + c - a + 3x2)2 + (c + a - b - 6x2)2 = 0 find the value of \(\sqrt {a+b+c}\) |
2x x -x ±x |
±x |
We know that if a2 + b2 + c2 = 0 a = 0 b = 0 c = 0 So, a + b - c = -2x2 b + c - a = -3x2 c + a - b = 6x2 By adding a + b + c = x2 \(\sqrt {a+b+c}\) = \(\sqrt {{x}^{2}}\) = ±x |
