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Home Questions QNTY355P2A
Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

Figure shows a rectangular conductor PQRS in which the conductor PQ is free to move. The conductor PQ is moved towards the left with a constant velocity V as shown in the figure. Assume that there is no loss of energy due to friction. What will be the magnetic flux linked with the loop PQRS and the motional emf?

Options:

Magnetic flux = $Bl(xV)$; Motional emf = $Blx$

Magnetic flux = $Blx$; Motional emf = $(BlV)/t$

Magnetic flux = $Blx$; Motional emf = $BIV$

Magnetic flux = $B/(lx)$; Motional emf = $BlV$

Correct Answer:

Magnetic flux = $Blx$; Motional emf = $BIV$

Explanation:

The correct answer is Option (3) → Magnetic flux = $Blx$; Motional emf = $BIV$

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