If $x^2+2xy +y^3=10,$ then value of $\frac{dy}{dx}$ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{-2(x+y)}{2x+3y^2}$
$x^2+2xy +y^3=10$
differentiating eq. wrt (x)
$2x+2y+2x\frac{dy}{dx}+3y^2\frac{dy}{dx}=0$
so $\frac{dy}{dx}=\frac{-2(x+y)}{2x+3y^2}$