If $\sin A=\frac{4}{5}$, then $(3-\tan A)(2+\cos A)=$

$\frac{12}{5}$ $\frac{13}{3}$ $\frac{13}{5}$ 3

$\frac{13}{3}$

The correct answer is Option (2) → $\frac{13}{3}$ $\sin A=\frac{4}{5}$ we know that, Sin = \(\frac{P}{H}\) = \(\frac{4}{5}\) So, we know that,  B2 = H2 - P2 B2 = 52 - 42 B = 3 Put the values in $(3-\tan A)(2+\cos A)=$ (3 - \(\frac{4}{3}\))(2 + \(\frac{3}{5}\)) = \(\frac{5}{3}\) (\(\frac{13}{5}\)) = $\frac{13}{3}$