If sin A=4/5, then (3-tan A)(2+cos A)=

The correct answer is Option (2) → $\frac{13}{3}$

$\sin A=\frac{4}{5}$

we know that,

Sin = \(\frac{P}{H}\) = \(\frac{4}{5}\)

So, we know that, 

B² = H² - P²

B² = 5² - 4²

B = 3

Put the values in $(3-\tan A)(2+\cos A)=$

(3 - \(\frac{4}{3}\))(2 + \(\frac{3}{5}\))

= \(\frac{5}{3}\) (\(\frac{13}{5}\))

= $\frac{13}{3}$