The average price of 3 items is Rs.3420 . If their price are in the ratio 3 : 5 : 2 , then the price of the costliest item is?
Answer & explanation
Correct answer: option 3
Total price = 3420 × 3 = 10,260
3R + 5R + 2R = 10R
10R = 10260
1R = \(\frac{10260}{10}\)
5R = \(\frac{10260 × 5}{10}\) = 5130
The price of the costliest item is = 5130