The average price of 3 items is Rs.3420 . If their price are in the ratio 3 : 5 : 2 , then the price of the costliest item is?

6350 5690 5130 7890

5130

Total price =  3420 × 3 = 10,260 3R + 5R + 2R = 10R 10R = 10260 1R =  \(\frac{10260}{10}\) 5R = \(\frac{10260 × 5}{10}\) =  5130 The price of the costliest item is =  5130