The cauchy schwartz inequality for any two vectors \(\vec{a}\) and \(\vec{b}\) is
Answer & explanation
Correct answer: option 2
$|\vec a.\vec b|=|\vec a||\vec b||\cos θ|$
as $0≤\cos θ≤1$
$⇒|\vec a.\vec b|≤|\vec a||\vec b|$ cauchy schwartz inequality
The cauchy schwartz inequality for any two vectors \(\vec{a}\) and \(\vec{b}\) is
Correct answer: option 2
$|\vec a.\vec b|=|\vec a||\vec b||\cos θ|$
as $0≤\cos θ≤1$
$⇒|\vec a.\vec b|≤|\vec a||\vec b|$ cauchy schwartz inequality