CUET Preparation Today
If $A=\begin{bmatrix}3 & 0 & -1\\2 & 3& 0\\0 & 4 & 1\end{bmatrix}$, then |adj(adj A)| is : |
0 4 2 1 |
1 |
The correct answer is Option (4) → 1 $A=\begin{bmatrix}3 & 0 & -1\\2 & 3& 0\\0 & 4 & 1\end{bmatrix}$ $|A|=3(3-0)-1(8-0)$ $=9-8=1$ $|Adj (A)|=|A|^{n-1}$ $=(1)^2=1$ [n = order of matrix] $⇒|Adj (Adj(A))|=|Adj (A)|^{n-1}$ $=(1)^2=1$ |
