Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

If $f(x)=x e^{x(1-x)}$, then f(x) is

Options:

increasing on $\left[-\frac{1}{2}, 1\right]$

decreasing R

increasing on R

decreasing on $\left[-\frac{1}{2}, 1\right]$

Correct Answer:

increasing on $\left[-\frac{1}{2}, 1\right]$

Explanation:

$f(x)=x e^{(1-x)} \Rightarrow f'(x)=e^{x(1-x)}+x e^{x(1-x)(1-2 x)}$

$\Rightarrow f'(x)=e^{x(1-x)}\left(1+x-2 x^2\right)$

i.e. if $1+x-2 x^2 \geq 0$, i.e. $2 x^2-x-1 \leq 0$

$\Rightarrow(2 x+1)(x-1) \leq 0 \Rightarrow -\frac{1}{2} \leq x \leq 1$.