Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(III), (C)-(IV), (D)-(I) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) |
The correct answer is Option (3) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
Each equation is reduced to linear form and integrating factor identified. (A) $x\frac{dy}{dx}-y=2x^2$ $\frac{dy}{dx}-\frac{1}{x}y=2x$ Integrating factor $=e^{\int -\frac{1}{x}dx}=e^{-\log x}=\frac{1}{x}$ (A) → (II) (B) $\frac{dy}{dx}+\frac{y}{x}=2x$ Integrating factor $=e^{\int \frac{1}{x}dx}=x$ (B) → (III) (C) $x\frac{dy}{dx}+2y=x^2\log x$ $\frac{dy}{dx}+\frac{2}{x}y=x\log x$ Integrating factor $=e^{\int \frac{2}{x}dx}=e^{2\log x}=x^2$ (C) → (IV) (D) $\frac{dx}{dy}-x=y$ $\frac{dx}{dy}-x=y$ is linear in $x$ with variable $y$ Integrating factor $=e^{\int (-1)dy}=e^{-y}$ (D) → (I) Final Matching: (A)-(II), (B)-(III), (C)-(IV), (D)-(I). |