What should be added to 1459 so that it is exactly divisible by 12?

4 3 5 6

5

When we divide 1459 with 12 we get 7 as remainder. Thus, for a number to be completely divisible by 12, the remainder should be 0. Thus, we will add 5 so that remainder 7 becomes 12 and then gets completely divided by 12 leaving remainder to be zero. 1459 + 5 = 1464 \(\frac{1464}{ 12}\) = 122