Statement I: Glucose gives a reddish-brown precipitate with Fehling’s solution
Statement II: Reaction of glucose with Fehling’s solution gives CuO and gluconic acid
Answer & explanation
Correct answer: option 3
The correct answer is option 3. Statement I is correct, but Statement II is false.
Statement I: Glucose gives a reddish-brown precipitate with Fehling’s solution
Statement I is correct. Glucose does give a reddish-brown precipitate with Fehling's solution. Fehling's solution is a chemical reagent commonly used for the detection of reducing sugars, such as glucose. When glucose is present in the solution and heated with Fehling's solution, it undergoes a redox reaction, reducing the copper ions (Cu²⁺) in Fehling's solution to form a reddish-brown precipitate of cuprous oxide (Cu₂O).
Statement II: Reaction of glucose with Fehling’s solution gives CuO and gluconic acid
Statement II is false. The reaction of glucose with Fehling's solution does not give CuO and gluconic acid. Instead, it forms cuprous oxide (Cu₂O) as the reddish-brown precipitate and reduces glucose to form an aldaric acid. In the case of glucose, it forms glucaric acid, not gluconic acid. The reaction is a redox reaction where glucose acts as a reducing agent.
Therefore, the correct answer is that Statement I is correct, but Statement II is false.