A conductance cell when filled with 0.5 M KCl solution (specific conductance = 6.67 x 10-3 Ω-1 cm-1) registers a resistance of 243 Ω. What is the cell constant?

1.62 cm 1.62 cm-1 1.62 dm-1 1.62 m-1

1.62 cm-1

Specific conductance = Conductance x cell constant Κ = G x σ Κ = \(\frac{1}{R}\) x σ 6.67 x 10-3 = \(\frac{1}{243}\) x σ σ = 6.67 x 10-3 x 243 = 1.62 cm-1