A conductance cell when filled with 0.5 M KCl solution (specific conductance = 6.67 x 10-3 Ω-1 cm-1) registers a resistance of 243 Ω. What is the cell constant?
Answer & explanation
Correct answer: option 2
Specific conductance = Conductance x cell constant
Κ = G x σ
Κ = \(\frac{1}{R}\) x σ
6.67 x 10-3 = \(\frac{1}{243}\) x σ
σ = 6.67 x 10-3 x 243 = 1.62 cm-1