Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

If $f(θ) =\begin{vmatrix}1&\tan θ&1\\-\tan θ&1&\tan θ\\-1&-\tan θ&1\end{vmatrix}$, then the set $\{f(θ):0≤θ≤\frac{π}{2}\}$ is

Options:

$(-∞, 0]∪[2,∞)$

$[2,∞)$

$(-∞, 0)∪(0,∞)$

$(-∞, -1]∪[1,∞)$

Correct Answer:

$[2,∞)$

Explanation:

Applying $R_1 → R_1 + R_3$, we get

$f(θ) =\begin{vmatrix}θ&0&2\\-\tan θ&1&\tan θ\\-1&-\tan θ&1\end{vmatrix}$

$=2 (\tan^2θ+1)=2 \sec^2 θ>2$

$∴f(θ) ∈[2,∞)$.