If A= (2, 3), B=(-1, 0), C= (4, 6) then area of the parallelogram ABCD is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3
$\vec{AB}=-3\hat i-3\hat j$
$\vec{BC}=5\hat i+6\hat j$
area = $|\vec{AB}×\vec{BC}|$
so $\vec{AB}×\vec{BC}=\begin{vmatrix}\hat i&\hat j&\hat k\\-3&-3&0\\5&6&0\end{vmatrix}$
$\vec{AB}×\vec{BC}=-3\hat k$
area = 3 sq. units