The derivative of sin^3(cos x^2) with respect to x i s:

The correct answer is option (1) → $-6x\sin^2(\cos x^2)\cos(\cos x^2)\sin^2x$

$\frac{d}{dx}\sin^3(\cos x^2)$

$=3\sin^2(\cos x^2)\cos(\cos x^2)(-\sin x^2)(2x)$

$=-6x\sin^2(\cos x^2)\cos(\cos x^2)(\sin x^2)$