The highest magnetic moment is shown by which transition metal ion with the given outermost electronic configuration?
Answer & explanation
Correct answer: option 1
Magnetic moment is given by,
υ = \(\sqrt {n(n+2) }\)
More the number of unpaired electrons, higher will be the magnetic moment.
In 3d5 configuration, no of unpaired electrons = 5
υ = \(\sqrt {5(5+2) }\) = \(\sqrt {5 × 7 }\) = \(\sqrt {35 }\) = 5.91 B.M