Practicing Success
The population of a town increased by 15% in 2018 and 10% in 2019. Due to a pandemic, it decreased by 10% in 2020. What was the percentage increase in the population of the town in 3 years? |
12.5% 17.5% 13.85% 15% |
13.85% |
Let present population = 100x According to question , Increased Population = \(\frac{100+10}{100}\) × \(\frac{100+15}{100}\) × \(\frac{100-10}{100}\) × 100x = \(\frac{110}{100}\) × \(\frac{115}{100}\) × \(\frac{90}{100}\) × 100x = 113.85x Percentage increase in population = \(\frac{113.85x}{100x}\) × 100 = 13.85% |