What should be the rate of change of potential difference across capacitor to establish an instantaneous displacement current of 1 A in the space between the two parallel plates of a 2 µF capacitor?

5 × 10⁵ V/s

Here, I_D = 1 Amp, and C = 2 µF

So $\frac{dV}{dt}=\frac{I_{D}}{C}=\frac{1}{2 \times 10^{-6}}=5 \times 10^5$ volt / sec.

Thus, a displacement current of 1 Amp. can be set up by changing the potential difference across the parallel plates of the capacitor at the rate of 5 × 10⁵ volt /sec.