Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:
What is the order and degree of the differential equation $(\frac{d^2s}{dt^2})^2+\frac{d^2s}{dt^2}+t\frac{ds}{dt}=0$?
Options:
order 2 degree 1
order 1 degree 2
order 1 degree 1
order 2 degree 2
Correct Answer:
order 2 degree 2
Explanation:
Highest order derivative is $\frac{d^2s}{dt^2}$. So order 2. The power of $\frac{d^2s}{dt^2}$ is 2 so degree 2.