Assertion (A) : An electron and a proton are accelerated through the same potential difference. The de-Broglie wavelength associated with the electron is longer.
Reason (R) : De-Broglie wavelength associated with a moving particle is \(\lambda\) = h/p where, p is the linear momentum.
Answer & explanation
Correct answer: option 2
Since, mass of electron is lesser than the mass of proton, de Broglie wavelength of proton is shorter than that of electron.