The value of $\frac{sin4θ}{(1-cos4θ)}$ is :

cot θ cot 2θ tan θ tan 2θ

cot 2θ

\(\frac{sin4θ}{1 - cos4θ}\) Put θ = 15º = \(\frac{sin60º}{1 - cos60º}\) = \(\frac{ √3/2}{1 - 1/2}\) = \(\frac{ √3/2}{ 1/2}\) = √3