A circuit element 'X' when connected to peak voltage of 200 V, a peak current of 5 A flows which lags behind the voltage by $\frac{\pi}{2}$. A circuit element Y when connected to same peak voltage, same peak current flows which is in phase with the voltage. Now X and Y are connected in series with same peak voltage. The rms value of current through the circuit will be:

2.5 A

The correct answer is Option (3) → 2.5 A