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Two thin slabs of refractive indices $\mu_1$ and $\mu_2$ are placed parallel to each other in the x - z plane. If the direction of propagation of a ray in the two media are along the vectors $\vec{r}_1=a \hat{i}+b \hat{j}$ and $\vec{r}_2=c \hat{i}+d \hat{j}$ then we have:
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$\mu_1 a=\mu_2 b$ $\frac{\mu_1 a}{\sqrt{a^2+b^2}}=\frac{\mu_2 c}{\sqrt{c^2+d^2}}$ $\mu_1\left(a^2+b^2\right)=\mu_2\left(c^2+d^2\right)$ none of these |
$\frac{\mu_1 a}{\sqrt{a^2+b^2}}=\frac{\mu_2 c}{\sqrt{c^2+d^2}}$ |
For snell's law, $\mu_1 \sin \theta_1=\mu_2 \sin \theta_2$ $\frac{\mu_1 a}{\sqrt{a^2+b^2}}=\frac{\mu_2 c}{\sqrt{c^2+d^2}}$ |
