Two thin slabs of refractive indices $\mu_1$ and $\mu_2$ are placed parallel to each other in the x - z plane. If the direction of propagation of a ray in the two media are along the vectors $\vec{r}_1=a \hat{i}+b \hat{j}$ and $\vec{r}_2=c \hat{i}+d \hat{j}$ then we have:
Answer & explanation
Correct answer: option 2
For snell's law,
$\mu_1 \sin \theta_1=\mu_2 \sin \theta_2$
$\frac{\mu_1 a}{\sqrt{a^2+b^2}}=\frac{\mu_2 c}{\sqrt{c^2+d^2}}$